Is it possible to calculate the difficulty purely by the number of blocks generated in e.g. 3 month and the staring difficulty?


Great explanation Augusto!

Need to clarify one thing regarding target.

1. Network takes some random number and it generates its hash

No, the target is not exactly a random number. The target is defined in accordance with the rate of blocks being accepted by the network each 10 minutes. So there is a defined formula to generate the target.

Let's examine a real case, the first block generated by Satoshi Nakamoto when he started the Bitcoin protocol. The Internet page provide a history of the blockchain in CSV format:


There is a field "time" followed by a field "target". The number...

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The difficulty index measures the difficulty associated with a given task. The task can be a test associated with an educational course, training program or a work-related task. This is why the index is used by teachers, professionals, trainers and corporate managers. The index is between 0 and 1 and presented in the form of a percentage.

Step 1

Determine what constitutes a successful result of the exercise or task you are looking to evaluate. As a simple example, assume you are looking to measure the difficulty index of a test administered in a classroom where 70 percent is a passing grade.

Step 2

Record the number of people participating in the exercise. In our example, assume 20 students will take the test.

Step 3

Record the number of people who completed the exercise successfully. In our example, assume 13 students pass the test.

Step 4

Calculate the difficulty index by dividing the number of people who completed the...

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Calculate difficulty of a given sentence. Here a Word is considered hard if it has 4 consecutive consonants or number of consonants are more than number of vowels. Else word is easy. Difficulty of sentence is defined as 5*(number of hard words) + 3*(number of easy words).


Input : str = "Difficulty of sentence" Output : 13 Hard words = 2(Difficulty and sentence) Easy words = 1(of) So, answer is 5*2+3*1 = 13

Asked in : Microsoft

Start traversing the string and perform following steps:-

Increment vowels count, if current character is vowel and set conecutive consonants count=0. Else increment consonants count, also increment consecutive consonants count. Check if consecutive consonants becomes 4, then current word is hard, so increment its count
and move to the next word.Reset all counts to 0. Else check if a word is completed and count of consonants is greater than count of vowels,
then it is a hard word else easy...
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Going through thread after thread I am consistently seeing a common misconception. The proper way to look at mining rig ROI rates is brought up in various places, but it is clearly being ignored en mass (i.e. the nooblets out there swarming in on our society).

Calculators like these below are simple calculations based on the current difficulty.

These provide a number of outputs revenue rates over different time scales.. Hr, Day, Month..year.. Which makes them very very misleading.

Let's walk through a couple scenarios and asses the current situation of the network, what difficulty rate increases are 'possible' and how hardware availability has an effect.

Example Scenario

If I were to pick up a Radeon 280x and get it hasing at ~700Kh (let's assume free electricity for the examples). One of these calculators...

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Difficulty is a measure of how difficult it is to find a new block. It is a human-friendly way of expressing the target.

How often does the difficulty change?

Every 2016 blocks.

What is the formula for difficulty?

Difficulty can be computed from the current target (which is a 256-bit number) as follows:

difficulty = 0xFFFF * 2**208 / target

How is difficulty stored in blocks?

Each block stores a packed representation (called "Bits") for its actual hexadecimal target. The target can be derived from it via a predefined formula. For example, if the packed target in the block is 0x1b0404cb, the hexadecimal target is

0x0404cb * 2**(8*(0x1b - 3)) = 0x00000000000404CB000000000000000000000000000000000000000000000000

Note that the 0x0404cb value is a signed value in this format. The largest legal value for this field is 0x7fffff. To make a larger value you must shift it down one full byte. Also 0x008000 is the smallest positive valid...

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Physicist: In a word: yes. But it’s not a problem in large populations.

The original questioner pointed out that in the age of Charlemagne (more or less when everybody’s 40-greats grandfolk were living) the world population was between 200 and 300 million, and yet 2^40 (the number of ancestors you would have with no overlap) is 1,099,511,627,776. As it happens, 1.09 trillion is bigger than 300 million (math!). That means that your average ancestor alive 1200 years ago shows up in your 40-generation-tall family tree at least around 4,000 times. That redundancy is likely to be much higher. Many of the people alive during the reign of Chuck the Great left no descendents, and while your family tree is probably wider than you might suspect, most of your ancestors probably came from only a few regions of the world. Most people will start seeing redundancy in their family tree within a dozen generations (small towns and all that). Fortunately, “redundancy” isn’t an issue as long as...

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